Question

What would be the reactant and reagent used to obtain 2,4 dimethylpentan-3-ol?

• A. Propanal and propyl magnesium bromide.
• B. 3 - Methylbutanal and 2 - methyl magnesium iodide.
• C. 2, 2-Dimethylpropanone and methyl magnesium iodide
• D. 2 - Methylpropanal and isopropyl magnesium iodide

Answer 1

The correct option is D 2 - Methylpropanal and isopropyl magnesium iodide

$16.\left(d\right):C{H}_3-\underset{C{H}_3}{\underset{|}{CH}}-\stackrel{H}{\stackrel{|}{C}}=O+(C{H}_3{)}_{2}CHMgI⟶$

2-Methylpropanal Isopropyl magnesium iodide

$(C{H}_3{)}_{2}CH-\stackrel{H}{\stackrel{|}{\underset{CH(C{H}_3{)}_2}{\underset{|}{C}}}}-OMgI\underrightarrow{H_{2}O}(C{H}_3{)}_{2}CH-\stackrel{H}{\stackrel{|}{\underset{CH(C{H}_3{)}_2}{\underset{|}{C}}}}-OH$

2,4- dimethylpentan-3-ol