What would you observe in the following case:
Sugar crystals are added to hard glass test tube containing concentrated sulphuric acid.
Concentrated sulphuric acid dehydrates sugar crystals, leaving behind carbon as the residue.
C12H22O11 + Conc. H2SO4 → 12C + 11H2O
What do you observe when sugar crystals are added to hard glass test tube containing conc. sulphuric acid?
What would you observe in the following cases?
(i) Sulphur trioxide is dissolved in water on a large scale.
(ii) Concentrated sulphuric acid is added to equal volumes of cold water.
(iii) 100 ml of 98% sulphuric acid is kept open.
(iv) Hot concentrated sulphuric acid is added to sodium chloride crystals.
(v) Dilute sulphuric acid is added to ferrous sulphate solution.
Take 5 mL water in a test tube and slowly and concentrated sulphuric acid. Touch the bottom of the test tube. What do you observe?