What would you observe in the following case:
Sugar crystals are added to hard glass test tube containing concentrated sulphuric acid.

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Solution

Concentrated sulphuric acid dehydrates sugar crystals, leaving behind carbon as the residue.

C₁₂H₂₂O₁₁ + Conc. H₂SO₄ → 12C + 11H₂O

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What would you observe in the following cases?
(i) Sulphur trioxide is dissolved in water on a large scale.
(ii) Concentrated sulphuric acid is added to equal volumes of cold water.
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(v) Dilute sulphuric acid is added to ferrous sulphate solution.

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What would you observe in the following case: Sugar crystals are added to hard glass test tube containing concentrated sulphuric acid.

Concentrated sulphuric acid dehydrates sugar crystals, leaving behind carbon as the residue. C12H22O11 + Conc. H2SO4 → 12C + 11H2O

What would you observe in the following case:
Sugar crystals are added to hard glass test tube containing concentrated sulphuric acid.

Concentrated sulphuric acid dehydrates sugar crystals, leaving behind carbon as the residue.

C₁₂H₂₂O₁₁ + Conc. H₂SO₄ → 12C + 11H₂O