Question

# What would you observe in the following cases? (i) Sulphur trioxide is dissolved in water on a large scale. (ii) Concentrated sulphuric acid is added to equal volumes of cold water. (iii) 100 ml of 98% sulphuric acid is kept open. (iv) Hot concentrated sulphuric acid is added to sodium chloride crystals. (v) Dilute sulphuric acid is added to ferrous sulphate solution.

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Solution

## (i) Sulphuric acid is obtained when sulphur trioxide is dissolved in water on a large scale. SO3 + H2O → H2SO4 (ii) When concentrated sulphuric acid is added to an equal volume of water, a large amount of heat is evolved as it is an exothermic process. As a result, the contents of the container may spill out. (iii) When 100 ml of 98% sulphuric acid is kept open, it absorbs moisture from the air due to its hygroscopic nature. Subsequently, the level of concentrated H2SO4 in the container rises. (iv) When hot concentrated sulphuric acid is added to sodium chloride crystals, sodium hydrogen sulphate is formed. ${\text{NaCl + H}}_{2}S{O}_{4}\stackrel{{\text{<200}}^{0}C}{\to }{\text{NaHSO}}_{4}\text{+ HCl}$ (v) No reaction occurs when dilute sulphuric acid is added to a ferrous sulphate solution.

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