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Question

What would you observe in the following cases?
(i) Sulphur trioxide is dissolved in water on a large scale.
(ii) Concentrated sulphuric acid is added to equal volumes of cold water.
(iii) 100 ml of 98% sulphuric acid is kept open.
(iv) Hot concentrated sulphuric acid is added to sodium chloride crystals.
(v) Dilute sulphuric acid is added to ferrous sulphate solution.

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Solution

(i) Sulphuric acid is obtained when sulphur trioxide is dissolved in water on a large scale.
SO3 + H2O → H2SO4
(ii) When concentrated sulphuric acid is added to an equal volume of water, a large amount of heat is evolved as it is an exothermic process. As a result, the contents of the container may spill out.

(iii) When 100 ml of 98% sulphuric acid is kept open, it absorbs moisture from the air due to its hygroscopic nature. Subsequently, the level of concentrated H2SO4 in the container rises.
(iv) W
hen hot concentrated sulphuric acid is added to sodium chloride crystals, sodium hydrogen sulphate is formed.
NaCl + H2SO4 <2000C NaHSO4 + HCl
(v) No reaction occurs when dilute sulphuric acid is added to a ferrous sulphate solution.


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