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Question

When 0.36 g of glucose was burned in a bomb calorimeter (Heat capacity 600JK1) the temperature rise by 10 K. Calculate the standard molar enthalpy of combustion (MJ/mole).

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Solution

Moles of substance=given massMolar mass

Moles of glucose=0.36180=0.002 moles
Molar enthalpy of combustion=heat capacity×rise in temperaturemoles of glucose
Molar enthalpy of combustion=600×100.002=3×106 J/mol=3 MJ/mol

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