Question

When 0.44g of colourless oxide of nitrogen occupies 224 mL at 1520 mm of HG and 273 degree Celsius , then the oxide is ???

Answer 1

The volume is 224 ml at 1520 mm Hg of pressure and 273 ${}^{\circ }$. Thus the volume at 760 mm of Hg and 0 ${}^{\circ }$ will be denoted by

$\frac{P_1{V}_1}{T_1}=\frac{P_2{V}_2}{T_2}$

$\frac{1521\times 0.224}{546}=\frac{760\times V_2}{273}$

$Thus{V}_2=0.224L$

$Since0.224L=0.44gram$

$Thus22.4L\left(1mole\right)is=\frac{0.44}{0.224}\times 22.4=44gram$

Hence in all the given options the compound having 44 gram of weight is

$N_{2}O$

.