When $10$ ml of $0.2 M$ solution of an acid is added to $250$ ml of a buffer solution with $p H = 6.34$ , the pH of the solution becomes $6.32$ . The buffer capacity of the solution is:

0.1

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0.2

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0.3

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0.4

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Solution

The correct option is D $0.4$
The expression for the buffer capacity is as follows:

Buffer capacity $= \frac{Number of moles of acid or base added per litre}{Change in pH}$ .

$10$ ml of $0.2 M$ acid is added to $250$ ml of a buffer solution.
Number of moles of acid added $= \frac{0.2 \times 10}{1000}$

Hence, the number of moles of acid added per litre $= \frac{0.2 \times 10}{1000} \times \frac{1000}{250} = 0.008$

Change in pH $= 6.34 - 6.32 = 0.02$

Substituting values in the above expression, we get

Buffer capacity $= \frac{0.008}{0.02} = 0.4$

Hence, the buffer capacity is $0.4$ .

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When 10 ml of 0.2 M solution of an acid is added to 250 ml of a buffer solution with pH=6.34, the pH of the solution becomes 6.32. The buffer capacity of the solution is:

When $10$ ml of $0.2 M$ solution of an acid is added to $250$ ml of a buffer solution with $p H = 6.34$ , the pH of the solution becomes $6.32$ . The buffer capacity of the solution is: