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Arrhenius Acid

When 100 mL...

Question

When $100$ mL of $0.1 M B a (O H)_{2}$ is neutralized with a mixture of $x$ mL of $0.1 M H C l$ and $y$ mL of $0.2 M$ $H_{2} S O_{3}$ using methyl orange indicator, what is value of $x$ and $y$ respectively?

A

200, 100

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B

100, 200

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C

300, 200

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D

200, 300

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Solution

The correct option is A $200, 100$
Methyl orange indicator indicates complete ionization of $H C l$ but first step is ionization of $H_{2} S O_{3}$ .
$H_{2} S O_{3} \to H^{⨁} + H S O_{3}^{⊝} (n = 1) (N = M \times 1)$
First case:
$B a (O H)_{2} \equiv H C l$
$N_{1} V_{1} = N_{2} V_{2}$
$0.1 \times 2 \times 100 \equiv x \times 0.1 \times 1$
$x = 200$ mL
Second case:
$B a (O H)_{2} \equiv H_{2} S O_{3}$
$N_{1} V_{1} = N_{2} V_{2}$
$(0.1 \times 2) \times 100 = 0.2 \times 1 \times y$
$y = 100$ mL

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Q. Given two mixtures: (A)

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In the mixture of $N a H C O_{3}$ and $N a_{2} C O_{3}$ volume of a given HCl required is 'x' ml with phenolphthalein indicator and further 'y' ml required with methyl orange indicator. Hence volume of $H C l$ for complete reaction of $N a H C O_{3}$ is

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