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Molarity

When 100mL ...

Question

When $100 m L$ each of $H C l$ and $N a O H$ solutions are mixed, $5.71 k J$ of heat was evolved. What is the molarity of two solutions? The heat of neutralisation of $H C l$ is $57.1 k J$ .

3 M

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0.5 M

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1 M

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2 M

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Solution

The correct option is C $1 M$
Heat of neutralisation = 57.1 KJ for 1 mole
Therefore, No. of moles = $\frac{5.71}{57.1}$ =0.1
Molarity= $\frac{m o l e s}{V o l u m e (i n L)}$ = $\frac{0.1}{100 \times 10^{- 3}}$
$= 1 M$

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