CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
162
You visited us 162 times! Enjoying our articles? Unlock Full Access!
Question

When 2 moles of C2H6 are completely burnt 3120 kJ of heat is liberated. Calculate the heat of formation,
Hf for C2H6. Given H0f for CO2(g) and H2O(l) are 395 and 286 kJ respectively.

Open in App
Solution

2C2H6+7O24CO2+6H2O

ΔHreaction=3120 kJ

ΔHreaction=(ΔHof)products(ΔHof)reactants

3120=[2×ΔHof(C2H6)+7×ΔHof(O2)]+[4×ΔHof(CO2)+6×ΔHof(H2O)]

3120=2×ΔHof(C2H6)+7×04×3956×286

2×ΔHof(C2H6)=312015801716

2×ΔHof(C2H6)=176

ΔHof(C2H6)=88 kJ


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Thermochemistry
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon