When $20.8 g$ of Barium chloride is added with $14.2 g$ of Sodium sulphate, $23.3 g$ of Barium sulphate and $11.7 g$ of Sodium chloride are formed. Show that these observations are in agreement with the law of conservation of mass.

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Solution

Step 1: Law of conservation of mass:
The law of conservation of mass states that mass can neither be created nor be lost but it can be conserved.
Thus, from the law of conservation of mass, the total mass of reactants is equal to the total mass of products in any chemical reaction.
Step 2: Identify reactants and products:
From the given data,
When $20.8 g$ of Barium chloride $({BaCl}_{2})$ is added with $14.2 g$ of Sodium sulphate $({Na}_{2} {SO}_{4})$ , $23.3 g$ of Barium sulphate $({BaSO}_{4})$ and $11.7 g$ of Sodium chloride $(NaCl)$ are formed.
${BaCl}_{2} (aq) + {Na}_{2} {SO}_{4} (aq) \to {BaSO}_{4} (s) + 2 NaCl (aq)$
Reactants are $20.8 g$ of Barium chloride and $14.2 g$ of Sodium sulphate.
Products are $23.3 g$ of Barium sulphate and $11.7 g$ of Sodium chloride.
Step 3: Apply the law of conservation of mass:
According to the law of conservation of mass,
Total mass of reactants $=$ Total mass of products
Thus,
Mass of Barium chloride $+$ Mass of Sodium sulphate $=$ Mass of Barium sulphate $+$ Mass of Sodium chloride
Thus,
$20.8 g + 14.2 g = 23.3 g + 11.7 g 35.0 g = 35.0 g$
Thus, the total mass of reactants and the total mass of products are equal.
Hence, the observations are in agreement with the law of conservation of mass.

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Q. Barium chloride reacts with sodium sulphate to form Barium sulphate and sodium chloride. Then, according to the law of conservation of mass:

barium chloride reacts with sodium sulphate to form barium sulphate and sodium chloride, in an experiment to verify the law of conservation of mass 20.8g of barium chloride reacted with 14.2g of sodium sulphate to form 11.7g of sodium chloride. the amount of barium sulphate formed in the above reaction will be : -

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(b) 23.7g

(d) 23.0g

(a) State the law of conservation of mass.

(b) What do you observe when barium chloride solution is mixed with sodium sulphate solution ?

Q. Neeta observed that a precipitate is formed when she adds:
a)barium chloride to sodium sulphate b)barium chloride to sodium chloride c)sodium sulphate to sodium chloride d)hydrochloric acid to barium chloride

Barium chloride on reacting with sodium sulphate forms barium sulphate and sodium chloride. Which of the following is the precipitate?

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When 20.8g of Barium chloride is added with 14.2g of Sodium sulphate, 23.3g of Barium sulphate and 11.7g of Sodium chloride are formed. Show that these observations are in agreement with the law of conservation of mass.

When $20.8 g$ of Barium chloride is added with $14.2 g$ of Sodium sulphate, $23.3 g$ of Barium sulphate and $11.7 g$ of Sodium chloride are formed. Show that these observations are in agreement with the law of conservation of mass.