When 22.4 L of C4H8 at STP is burnt completely, 89.6 L of CO2 gas at STP and 72 g of water are produced. The volume of the oxygen gas at STP consumed in the reaction is closest to :
134.4 L
C4H8 + 6O2 → 4CO2 + 4H2O
22.4 lit89.6 lit. 72 g
At S.T.P. at S.T.P.
1 mole 4 mole 7218=4mole
For complete combustion of 1 mole C4H8
6 mole O2 required
nO2=6mole
VO2=6×22.4
VO2=134.4lit.