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Standard X
Chemistry
Atom
when 22.4 l o...
Question
when 22.4 l of H2 is mixed with 11.2 l of Cl2, each at STP, the moles of HCL formed is equal to?
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Q.
When
22.4
litres of
H
2
(
g
)
is mixed with
11.2
litres of
C
l
2
(
g
)
, each at STP, the moles of HCl(g) formed is equal to :
Q.
When 22.4 litres of
H
2
(
g
)
is mixed with 11.2 litres of
C
l
2
(
g
)
, each at S.T.P., the moles of HCl(g) formed is equal to:
Q.
M
n
O
2
+
4
H
C
l
⟶
M
n
C
l
2
+
2
H
2
O
+
C
l
2
2
moles
M
n
O
2
reacts with
4
moles of
H
C
l
to form
11.2
L
C
l
2
at STP. Thus, percent yield of
C
l
2
is
:
Q.
11.2
L
of
C
H
4
and
22.4
L
of
C
2
H
6
at
S
T
P
are mixed. Then the correct statement(s) is/are:
Q.
Four cylinders are filled with 11.2 L of
H
2
, 5 L of
O
2
, 22.4 L of
N
2
and 8 L of
Cl
2
gases. Which cylinder contains the maximum number of molecules at STP?
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