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Question

When (±)-2,3-dibromobutane reacts with KOH, trans-2-bromobut-2-ene is formed. Which of the following is/are true?


A

The reaction proceeds via E2

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B

The reaction proceeds via E1

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C

Both enantiomers give the same product

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D

This elimination is also known as β elimination

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Solution

The correct option is D

This elimination is also known as β elimination


For E2, we need carbon-hydrogen and the carbon-bromine bonds to be anti-periplanar.
They should be coplanar but the CBr and CH bonds should be on opposite sides.

After rotation, the antiperiplanar structure is in place for E1:

For the other enantiomer from the racemic mixture, E2 looks like:


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