Question

When $30\mu C$ charge is given to an isolated conductor of capacitance $5\mu F$ . If this conductor is now connected to another isolated conductor by a conducting wire (at very large distance) of total charge $50\mu C$ and capacity $10\mu F$ then find out the common potential of both the conductors.

Answer 1

The potential of the capacitor is given as

$C=\frac{q}{V}$

Then by using the above formula we can calculate the potential on first capacitor

$V_1=\frac{30\mu C}{5\mu F}$

Similarly

$V_2=\frac{50\mu C}{10\mu F}$

The common potential is given as

$C_1{V}_1+C_2{V}_2=V\left(C_1+C_2\right)$

The common potential is given as

$3\times {10}^{-5}+5\times {10}^{-5}=V\left(15\times {10}^{-6}\right)$

$V=0.533V$