Question

When $9.65$ ampere current was passed for $1.0$ hour into nitrobenzene in acidic medium, the amount of p-aminophenol produced is _______.

• A. $10.9g$
• B. $109.0g$
• C. $9.81g$
• D. $98.1g$

Answer 1

Answer: (C)

$9.81g$

9.65 ampere current was passed for 1.0 hour (3600 seconds)

Number of moles of electrons passed $=\frac{I\left(A\right)\times t\left(s\right)}{96500}=\frac{9.65A\times 3600s}{96500}=0.36$ moles

4 moles of electrons will reduce 1 mole of nitrobenzene to p-aminophenol.

0.36 moles of electrons will reduce $\frac{0.36}{4}=0.09$ moles of nitrobenzene to p-aminophenol.

p-aminophenol molar mass 109.14 g/mol

Mass of p-aminophenol obtained $=109.14g/mol\times 0.09mol=9.81g$