When $_{92} U^{235}$ undergoes fission by absorbing $_{0} n^{1}$ producing $_{56} B a^{144}$ and $_{36} K r^{89}$ The number of neutrons produced will be

2

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3

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1

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0

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Solution

The correct option is C $3$
When $_{92} U^{235}$ undergoes fission-by absorbing $_{0} n^{1}$ , the products produced are $_{56} B a^{144}$ and $_{36} K r^{89}$ . The number of neutrons produced are three.
The correct option is B.

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Similar questions

_{92}^{235} U

_{0}^{1} n

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Calculate the number of neutrons emitted when $_{92} U^{235}$ undergoes controlled nuclear fission to $_{54} X e^{142}$ and $_{38} S r^{90} .$

(IIT-JEE, 2010)

Calculate the number of neutrons emitted when $_{92} U^{235}$ undergoes controlled nuclear fission to $_{54} X e^{142}$ and $_{38} S r^{90} .$

(IIT-JEE, 2010)

_{92} U^{235}

_{54} {X e}^{139}

_{38} {S r}^{94}

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