When a 0.5 kW heater operates for 20 minutes, the electrical energy consumed is equal to ___ kJ.

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Solution

0.5 kW = $0.5 \times 1000 w a t t s$ = 500 W

Energy consumed in 1 second = 500 J ( $∵ 1 w a t t = \frac{1 j o u l e}{1 ‘ s}$ )

Energy consumed in 20 minutes = $500 \times 20 \times 60 J$ ( $∵ 1 m i n u t e = 60 s$ )

= 600000 J

= 600 kJ

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