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Question

When a 0.5 kW heater operates for 20 minutes, the electrical energy consumed is equal to ___kJ.


Solution

Step 1:- 0.5 kW = 0.5×1000 watts

Step 2:-Energy consumed in 1 sec = 500 J

Energy consumed in 20 minutes = 500×20×60J

= 600000 J

= 600 kJ


Physics

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