When a 0.5 kW heater operates for 20 minutes, the electrical energy consumed is equal to ___kJ.

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Solution

Step 1:- 0.5 kW = $0.5 \times 1000 w a t t s$

Step 2:-Energy consumed in 1 sec = 500 J

Energy consumed in 20 minutes = $500 \times 20 \times 60 J$

= 600000 J

= 600 kJ

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