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Question

# When a 2 μC charge is carried from point A to point B, the amount of workdone by the electric field is 50 μJ. Find the potential difference and also find which point is at a higher potential.

A
25 V , B
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B
25 V , A
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C
20 V , B
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D
Both are at the same potential.
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Solution

## The correct option is B 25 V , AGiven, Charge of the particle q=2 μC Workdone by the electric field W=50 μJ We know, workdone by electric field on a particle of charge q moving between two points A and B is given by W=q(VA−VB) ⇒VA−VB=Wq Substituting the given data we get, VA−VB=50×10−62×10−6=25 V From this, we can say that VA>VB Hence, option (b) is the correct answer.

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