When a ball is thrown up vertically with velocity v0, it reaches a maximum height of h. If one wishes to triple the maximum height, then the ball should be thrown with velocity.
A
√3v0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
3v0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
9v0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
32v0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A√3v0 Using the 3rd equation of motion, v2−u2=2as ⇒O−v2∘=2ah ⇒v2∘=2gh (Upward is taken as positive) ∴h∝v2∘ ∴ to triple the maximum height, ball should be thrown with √3v∘