Question

When a ball is thrown up vertically with velocity $v_0$, it reaches a maximum height of $h$ If one wishes to triple the maximum height then the ball should be thrown with velocity:

• A. $\sqrt{3}{v}_0$
• B. $3v_0$
• C. $9v_0$
• D. $3/2v_0$

Answer 1

The correct option is A $\sqrt{3}{v}_0$

$h=\frac{v_0^2}{2g}$
$h^{\prime }=3h=\frac{3v_0^2}{2g}=\frac{(\sqrt{3}{v}_0{)}^2}{2g}\Rightarrow v^{\prime }=\sqrt{3}{v}_0$