When a ball is thrown vertically upwards with velocity v0, it reaches a maximum height of h. With what velocity should the ball be thrown to reach half the maximum height.
A
√2v0
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B
√0.5v0
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C
√1.5v0
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D
√3v0
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Solution
The correct option is B√0.5v0 By using third equation of motion v2−u2=2as ⇒v2−v20=2gh ⇒v20=2gHmax (at h=Hmax,v=0) ⇒Hmax∝v20 ⇒v0∝√Hmax
i.e., to half the maximum height, ball should be thrown with velocity √0.5v0.