Question

When a brown compound of Mn(A) is treated with $HCl$, it gives a gas B. The gas B taken in excess reacts with $N{H}_3$ to give an explosive compound C. The compounds A, B and C are:

• A. $A=Mn{O}_2,B=C{l}_2,C=NC{l}_3$
• B. $A=MnO,B=C{l}_2,C=N{H}_{4}Cl$
• C. $A=M{n}_3{O}_4,B=C{l}_2,C=NC{l}_3$
• D. $A=Mn{O}_3,B=C{l}_2,C=NC{l}_2$

Answer 1

Answer: (C)

$A=M{n}_3{O}_4,B=C{l}_2,C=NC{l}_3$

When brown compound $M{n}_3{O}_4$ is treated with $HCl$, it gives chlorine gas.

$M{n}_3{O}_4+8HCl\to 3MnC{l}_2+4H_{2}O+C{l}_2\uparrow$
Chlorine gas taken in excess reacts with ammonia to give an explosive compound $NC{l}_3$.
$N{H}_3+3C{l}_2\left(excess\right)\to NC{l}_3+3HCl$

The compounds A, B and C are $A=M{n}_3{O}_4,B=C{l}_2,C=NC{l}_3$