Question

When a capillary tube is immersed in a liquid, then liquid of mass $M$ rises in the capillary tube. If capillary tube of double radius is taken then mass of same liquid rising in the tube is:

• A. $\frac{M}{2}$
• B. $2M$
• C. $\frac{M}{4}$
• D. $4M$

Answer 1

The correct option is B $2M$

surface tension T=$\frac{\rho ghr}{2}=\frac{\rho g{h}^{\prime }{r}^{\prime }}{2}$

$r^{\prime }=2r$ and $h^{\prime }=\frac{h}{2}$

$M=\rho \pi r^{2}h$

$M^{\prime }=\rho \pi r^{\prime 2}{h}^{\prime }=2M$