When a capillary tube of radius $0.2 m m$ is dipped vertically in water of surface tension $0.072 N m^{- 1}$ and of angle of contact is $0^{o}$ , the weight of water supported by surface tension in the capillary tube is _____ $N$ .

90.5 \times 10^{- 6}

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90.5 \times 10^{6}

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90.5 \times 10^{- 5}

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90.5 \times 10^{5}

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Solution

The correct option is D $90.5 \times 10^{- 6}$
Force due to surface tension
$F = T \times 2 π r c o s θ$ , $θ = 0$
So the weight of water supported is F
$F = 90.4 \times 10^{- 6} N$

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When a capillary tube of radius 0.2 mm is dipped vertically in water of surface tension 0.072 Nm−1 and of angle of contact is 0o , the weight of water supported by surface tension in the capillary tube is _____ N.

The correct option is D 90.5×10−6Force due to surface tensionF=T×2πrcosθ , θ= 0So the weight of water supported is F F=90.4×10−6N

When a capillary tube of radius $0.2 m m$ is dipped vertically in water of surface tension $0.072 N m^{- 1}$ and of angle of contact is $0^{o}$ , the weight of water supported by surface tension in the capillary tube is _____ $N$ .

The correct option is D $90.5 \times 10^{- 6}$
Force due to surface tension
$F = T \times 2 π r c o s θ$ , $θ = 0$
So the weight of water supported is F
$F = 90.4 \times 10^{- 6} N$