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Question

When a certain photosensitive surface is illuminated with monochromatic light of frequency v, the stopping potential for the photocurrent is V02. When the surface is illuminated by monochromatic light of frequency v2, the stopping potential is V0. the threshold frequency for photoelectric emission is:

A
3v2
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B
2v
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C
43v
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D
5v3
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Solution

The correct option is C 3v2
hν=W+vo2e
hν2=W+voe
on solving we get, W=3/2hν
hvo=3/2hν
vo=3/2v

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