When a galvanometer is shunted with a $6 Ω$ resistance, the deflection is reduced to one third. If galvanometer is further shunted with a resistance of $3 Ω$ , the deflection is reduced to (relative to first reading)

one - sixth

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one - fifth

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one - seventh

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two - third

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Solution

The correct option is C one - seventh
$S = \frac{G}{n - 1}; 6 = \frac{G}{3 - 1} G = 6 \times 2 = 12 (n_{1} - 1) = \frac{G}{S_{1}} = \frac{12}{(\frac{6 \times 3}{9})} = \frac{12}{2} (n_{1} - 1) = 6; n_{1} = 7; I_{g} = \frac{I}{7}$

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When a galvanometer is shunted with a 6Ω resistance, the deflection is reduced to one third. If galvanometer is further shunted with a resistance of 3Ω, the deflection is reduced to (relative to first reading)

The correct option is C one - seventhS=Gn−1;6=G3−1G=6×2=12(n1−1)=GS1=12(6×39)=122(n1−1)=6;n1=7;Ig=I7

When a galvanometer is shunted with a $6 Ω$ resistance, the deflection is reduced to one third. If galvanometer is further shunted with a resistance of $3 Ω$ , the deflection is reduced to (relative to first reading)

The correct option is C one - seventh
$S = \frac{G}{n - 1}; 6 = \frac{G}{3 - 1} G = 6 \times 2 = 12 (n_{1} - 1) = \frac{G}{S_{1}} = \frac{12}{(\frac{6 \times 3}{9})} = \frac{12}{2} (n_{1} - 1) = 6; n_{1} = 7; I_{g} = \frac{I}{7}$