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Question

When a galvanometer is shunted with a 4Ω resistance, the deflection is reduced to one-fifth. If the galvanometer is further shunted with is further shunted with a 2Ω wire (2Ωand4Ω resistors are connected in parallel), the further reduction in the deflection will be(the main current remains the same).

A

(813) of the deflection when shunted with 4Ω only

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B

(513) of the deflection when shunted with 4Ω only

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C

(34) of the deflection when shunted with 4Ω only

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D

(313) of the deflection when shunted with 4Ω only

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Solution

The correct option is A (813) of the deflection when shunted with 4Ω only Case I : Rg×15=(I−15)×4⇒Rg=16Ω Case II : 16l1=4×26(l−l1)⇒l1=l13 So decrease in current to previous current =l5−l13l5

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