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Question

A galvanometer shows a reading of 0.65 mA. When a galvanometer is shunted with a 4 Ω resistance, the deflection is reduced to 0.13 mA. If the galvanometer is further shunted with a 2 Ω wire, the new reading will be (the main current remains the same)

A
0.60 mA
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B
0.08 mA
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C
0.12 mA
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D
0.05 mA
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Solution

The correct option is D 0.05 mA
Given I=0.65 mA
When shunted with resistance of 4 Ω, galvanometer reading is I=0.13 mA
I=44+GI44+G=15
G=16 Ω

When galvanometer is further shunted with 2 Ω resistance, Req=2×42+4=43
let galvanometer reading be I′′


I′′=4/343+16I
I"=113I=0.05 mA

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