When a golf ball is lowered into a measuring cylinder containing water, the water level rises by 30 cm³ when the ball is completely submerged. If the mass of ball in air is 33 g, find its density.

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Solution

ρ (density of golf ball) = ?
V (volume of steel piece) = 30 cm³
m (mass of steel piece) = 33 g
$ρ = \frac{m}{V} = \frac{33}{30}$
ρ = 1.1 g/cm³
Ans: Density of the golf ball = 1.1 g/cm³.

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When a golf ball is lowered into a measuring cylinder containing water, the water level rises by 30 cm3 when the ball is completely submerged. If the mass of ball in air is 33 g, find its density.

ρ (density of golf ball) = ? V (volume of steel piece) = 30 cm3 m (mass of steel piece) = 33 g ρ=mV =3330 ρ = 1.1 g/cm3 Ans: Density of the golf ball = 1.1 g/cm3.

When a golf ball is lowered into a measuring cylinder containing water, the water level rises by 30 cm³ when the ball is completely submerged. If the mass of ball in air is 33 g, find its density.

ρ (density of golf ball) = ?
V (volume of steel piece) = 30 cm³
m (mass of steel piece) = 33 g
$ρ = \frac{m}{V} = \frac{33}{30}$
ρ = 1.1 g/cm³
Ans: Density of the golf ball = 1.1 g/cm³.