When a golf ball is lowered into a measuring cylinder containing water,the water level rises by 30 $c m^{3}$ when the ball is completely submerged.If the mass of ball in air is 33 g,find its density.

Open in App

Solution

Given, change in volume of water when the ball is submerged = $30 c m^{3}$
Now, the volume of water displaced = volume of ball immersed fully
Hence volume of ball = $30 c m^{3}$
Mass = 33 g
So $D e n s i t y = \frac{m a s s}{v o l u m e} = \frac{33}{30} g c m^{- 3}$

$= 1.1 g c m^{- 3}$

Suggest Corrections

Similar questions

Q. When a golf ball is lowered into a measuring cylinder containing water,the water level rises by 30

c m^{3}

when the ball is completely submerged. If the mass of ball in air is 33 g, what would be its density?

The mass of a ball in air is $48 g$ . It is immersed in water contained in a measuring cylinder. The water level rises by $20 c m^{3}$ when the ball is completely submerged. What is the density of the ball?

A. $4.8 g c m^{- 3}$
B. $0.42 g c m^{- 3}$
C. $2.0 g c m^{- 3}$
D. $2.4 g c m^{- 3}$

Q. A tall measuring jar contains ethyl alcohol of density

0.8 g m / c m^{3}

. An iron ball is dropped into it and the level rises by

20 c m^{3}

. The buoyant force acting on the ball is : (Take acceleration due to gravity to be

10 m s^{- 2}

)

Q. Two identical lead balls are immersed into a measuring jar containing water, the level of water raises from 26 cm

^{3}

to 38 cm

^{3}

. If one of the above lead ball and another metallic ball are immersed simultaneously than level of water in measuring jar rises from 26 cm

^{3}

to 36 cm

^{3}

. Find the volume of the lead ball and metallic ball.

Q. Two identical lead bells are immersed into a measuring jar containing water, the level of water raises from

26

^{3}

to 38 cm

^{3}

. If one of the above lead ball and another metallic ball is immersed simultaneously than the level of water in measuring jar rise from

28

^{3}

to 36 cm

^{3}

. Find the volume of the lead ball and metallic ball.

Join BYJU'S Learning Program

When a golf ball is lowered into a measuring cylinder containing water,the water level rises by 30 cm3 when the ball is completely submerged.If the mass of ball in air is 33 g,find its density.

Given, change in volume of water when the ball is submerged = 30 cm3 Now, the volume of water displaced = volume of ball immersed fully Hence volume of ball = 30 cm3 Mass = 33 g So Density=massvolume=3330 g cm−3 =1.1 g cm−3

When a golf ball is lowered into a measuring cylinder containing water,the water level rises by 30 $c m^{3}$ when the ball is completely submerged.If the mass of ball in air is 33 g,find its density.

Given, change in volume of water when the ball is submerged = $30 c m^{3}$
Now, the volume of water displaced = volume of ball immersed fully
Hence volume of ball = $30 c m^{3}$
Mass = 33 g
So $D e n s i t y = \frac{m a s s}{v o l u m e} = \frac{33}{30} g c m^{- 3}$

$= 1.1 g c m^{- 3}$