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Question

When a junction diode is reverse biased, the current called drift current is due to

A
majority charge carriers of both n- and p-side.
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B
minority charge carriers of both n- and p-side.
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C
holes of both n- and p-side.
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D
conduction band electrons of n-side only.
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Solution

The correct option is C minority charge carriers of both n- and p-side.
In reverse bias condition, the positive terminal is connected to the n-type and the negative terminal is connected to the p-type. Hence, majority charge carriers are swept into terminals and minority charge carriers are repelled by the terminals. Thus, a very small drift current flows through the diode due to minority charge carriers of both n-side and p-side.

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