When a metal X is treated with cold water, it gives a basic salt Y with molecular formula XOH (Molecular mass = 40) and liberates a gas Z which easily catches fire. Identify X, Y, and Z and also write the reaction involved.

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Solution

$NaOH$ has a molecular weight of 40, X must be sodium.
$NaOH$ has a molecular weight of,
$Na (1 \times 23) + O (1 \times 16) + H (1 \times 1) = 40$
$NaOH$ is Y.
Z is a hydrogen gas that burns up very rapidly.
$2 Na (s) + 2 H_{2} O (l) \to 2 NaOH (s) + H_{2} (g)$
Sodium Water Sodium hydroxide Hydrogen gas
As a result, the following reaction is obtained regarding how sodium and cold water react:
$2 Na (s) + 2 H_{2} O (l) \to 2 NaOH (s) + H_{2} (g)$
Sodium Water Sodium hydroxide Hydrogen gas

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