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Question

When a mixture of 1−hexanol and hexanoic acid in diethyl ether is shaken with an aqueous NaHCO3 solution, then which of the following is right distribution?

A
In ether: sodium hexaonate ; In NaHCO3: 1hexanol
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B
In ether: 1hexanol ; In NaHCO3: hexanoic acid
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C
In ether: 1hexanol ; In NaHCO3: sodium hexanoate
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D
In ether: hexanoic acid ; In NaHCO3: 1hexanol
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Solution

The correct option is C In ether: 1hexanol ; In NaHCO3: sodium hexanoate
When a mixture of 1−hexanol and hexanoic acid in diethyl ether is shaken with an aqueous NaHCO3 solution, Hexanoic acid will react with NaHCO3 to form sodium hexanoate.

CH3CH2CH2CH2CH2COOH+NaHCO3CH3(CH2)4COONa+H2O+CO2

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