  Question

When a person throws a meter stick it is found that the centre of the stick is moving with a speed of $$10{\text{ }}m/s$$ vertically upwards & left end of stick with a speed of $$20{\text{ }}m/s$$ vertically upwards. Then the angular speed of the stick is:

A  B  C  D
None of the above  Solution

The correct option is A $$20\,\,rad/\sec$$Given: when a person throws a meter stick it is found that the centre of the stick is moving with a speed of 10 m/s vertically upwards & left end of stick with a speed of 20 m/s vertically upwards. To find the angular speed of the stick Solution:Let $$r$$ be the distance between the end point and center of the stickHere$$r=\dfrac l2=\dfrac 12m$$As per the given criteria,speed of center of the stick, $$v=10m/s$$and speed of left end of the stick, $$V_P=20m/s$$And $$V_P=v+r\omega\\\implies 20=10+\dfrac 12\omega\\\implies \omega=20rad/s$$is the angular speed of the stick Physics

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