CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

When a person throws a meter stick it is found that the centre of the stick is moving with a speed of $$10{\text{ }}m/s$$ vertically upwards & left end of stick with a speed of $$20{\text{ }}m/s$$ vertically upwards. Then the angular speed of the stick is:



A
20rad/sec
loader
B
10rad/sec
loader
C
30rad/sec
loader
D
None of the above
loader

Solution

The correct option is A $$20\,\,rad/\sec $$
Given: when a person throws a meter stick it is found that the centre of the stick is moving with a speed of 10 m/s vertically upwards & left end of stick with a speed of 20 m/s vertically upwards. 
To find the angular speed of the stick 
Solution:
Let $$r$$ be the distance between the end point and center of the stick
Here
$$r=\dfrac l2=\dfrac 12m$$
As per the given criteria,
speed of center of the stick, $$v=10m/s$$
and speed of left end of the stick, $$V_P=20m/s$$
And 
$$V_P=v+r\omega\\\implies 20=10+\dfrac 12\omega\\\implies \omega=20rad/s$$
is the angular speed of the stick 

Physics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image