1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# When a person throws a meter stick, it is found that the centre of the stick is moving with a speed of 10 m/s vertically upward & the left end of the stick with a speed 20 m/s vertically upward. Then, the angular speed of the stick is

A
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of the these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is A 20 rad/sec Assume angular velocity of the stick is ω rad/s in clockwise direction. For meter stick, L=1 m Speed of left end of the stick VA=20 m/s As we know, −→VA=→V0+→ω×−−→rAO {−−→rAO=−12^i} ⇒20^j=10^j+ω(−^^k)×12(−^i) ⇒10^j=ω2(^k×^i)[∵^k×^i=^j] ⇒10^j=ω2^j ∴ω=20 rad/s [ω is positive hence, assumed direction is correct.]

Suggest Corrections
4
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program