When a point source of light is at a distance of 50 cm from a photoelectric cell, the cut off voltage is found to be $V_{0}$ . If the same source is placed at a distance of 1 m from the cell, the cut off voltage will be

\frac{V_{0}}{4}

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\frac{V_{0}}{2}

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V_{0}

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2 V_{0}

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Solution

The correct option is C $V_{0}$
When the distance of the source from the cell is increased, the intensity of light falling on the cell decreases; but the cut-off voltage of the cell is independent of the intensity of the incident radiation. Hence, the correct choice is (c).

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When a point source of light is at a distance of 50 cm from a photoelectric cell, the cut off voltage is found to be V0. If the same source is placed at a distance of 1 m from the cell, the cut off voltage will be

The correct option is C V0When the distance of the source from the cell is increased, the intensity of light falling on the cell decreases; but the cut-off voltage of the cell is independent of the intensity of the incident radiation. Hence, the correct choice is (c).

When a point source of light is at a distance of 50 cm from a photoelectric cell, the cut off voltage is found to be $V_{0}$ . If the same source is placed at a distance of 1 m from the cell, the cut off voltage will be

The correct option is C $V_{0}$
When the distance of the source from the cell is increased, the intensity of light falling on the cell decreases; but the cut-off voltage of the cell is independent of the intensity of the incident radiation. Hence, the correct choice is (c).