When a sound wave of frequency 300 Hz passes through a medium, the maximum displacement of the particle of the medium is 0.1 cm. The maximum velocity of the particle will be:
A
60 m/s
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B
30 m/s
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C
30π cm/s
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D
60π cm/s
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Solution
The correct option is B60π cm/s The displacement of the particle of the medium is: x=Asin(kx−ωt) Velocity of the particle of the medium is: v=Aωcos(kx−ωt) Max velocity of the particle vmax=Aω=A×2πf=0.1×2×π×300=60πcm/s