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Question

When a spring is stretched by 2cm, it stores 100J of energy. If it is stretched further by 2cm, the stored energy will be increased by (in J)

A
100
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B
200
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C
300
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D
400
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Solution

The correct option is C 300
Initial energy =100=0.5×k×0.022
k=50×104N/m
Final energy =0.5×50×104×(0.02+0.02)2=400J
Increase in energy =400100=300J

Hence correct answer is option C

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