You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Scalar Triple Product

When a system...

Question

When a system is taken from state $1 t o 2$ along the path $1 a 2$ it absorbs $50 c a l$ of heat and work done is $20 c a l$ . Along the path $1 b 2$ , $Q = 36 c a l$ . What is the work done along $1 b 2$ ?

56 c a l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

66 c a l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

16 c a l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6 c a l

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $6 c a l$
Using first law we have $d U = d Q - d W$ .
Thus for process $1 a 2$ we have $d U = 50 - 20 = 30 c a l$

The change in internal energy in the process $1 b 2$ would be the same as internal energy is the point function.
Thus for process $1 b 2$ we have $d U = 30 = 36 - W$ or work done is $6 c a l$ .

Suggest Corrections

Similar questions

Q. When a system is taken from state i to state f along the path iaf, it is found that

Q = 50 c a l

and

W = 20 c a l

. Along the path ibf,

Q = 36 c a l

, W along the path

^{'} i b f^{'}

is :

Q. When a system is taken from state

i

to state

f

along the path

i a f

, it is found that

Q = 50 c a l

and

W = 20 c a l

. Along the path

i b f

Q = 36 c a l

W

along the path

i b f

is :

Q. When a system is taken from the state 'a' to state 'b' along the path 'acb', it is found that a quantity of heat

Q = 200 J

is absorbed by the system and a work

W = 80 J

is done by it. Along the path 'adb',

Q = 144 J

. The work done along the path 'adb' is

Q. When a system is taken from state 'a' to state 'b' along the path 'acb' it is found that a quantity of heat Q = 200 J is absorbed by the system and a work w = 80J is done by it. Along the path 'abd' Q = 144 J The work done along the path 'adb' is:

Q. When a system is taken from a state

i

f

along the path

i a f

(as shown in the figure).

Q = 50 c a l

and

W = 20 c a l

; along path

i b f

Q = 36 c a l

(i) What is

W

along path

i b f

?
(ii) If

W = 13

cal for path

f i

, what is

Q

for the path

f_{i}

?
(iii) Take

E_{i n t, i} = 10 c a l

then what is

E_{i n t, f}

Join BYJU'S Learning Program

When a system is taken from state 1 to 2 along the path 1a2 it absorbs 50 cal of heat and work done is 20 cal. Along the path 1b2, Q=36 cal. What is the work done along 1b2?

The correct option is D 6 calUsing first law we have dU=dQ−dW. Thus for process 1a2 we have dU=50−20=30calThe change in internal energy in the process 1b2 would be the same as internal energy is the point function. Thus for process 1b2 we have dU=30=36−W or work done is 6 cal.

When a system is taken from state $1 t o 2$ along the path $1 a 2$ it absorbs $50 c a l$ of heat and work done is $20 c a l$ . Along the path $1 b 2$ , $Q = 36 c a l$ . What is the work done along $1 b 2$ ?