CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
344
You visited us 344 times! Enjoying our articles? Unlock Full Access!
Question

When a system is taken from state 'a' to state 'b' along the path 'acb' it is found that a quantity of heat Q = 200 J is absorbed by the system and a work w = 80J is done by it. Along the path 'abd' Q = 144 J The work done along the path 'adb' is:
880420_c625783767a545759d14845c01b896a0.png

A
6 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
12 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
18 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
24 J
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is C 24 J
Since U depends only on the state at a and b but not on the path travelled
U remains the same for the path acb and adb
(U)1=(U)2
(Q+W)1 =(Q+W)2 as work done by the system decreases its internal energy
20080=144+W
W=24J (since Work done in path 1 is negative)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Theory of Equipartitions of Energy
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon