When a system is taken from state 'a' to state 'b' along the path 'acb' it is found that a quantity of heat Q = 200 J is absorbed by the system and a work w = 80J is done by it. Along the path 'abd' Q = 144 J The work done along the path 'adb' is:
A
6 J
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B
12 J
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C
18 J
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D
24 J
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Solution
The correct option is C 24 J Since △U depends only on the state at a and b but not on the path travelled
△U remains the same for the path acb and adb
(△U)1=(△U)2
(Q+W)1 =(Q+W)2 as work done by the system decreases its internal energy