When a system is taken from state -a- to state -b- along the path -acb- it is found that a quantity of heat Q -200 J is absorbed by the system and a Iwork W-80 J is done by it- Along the path -adb- Q -144 J- The work done along the path -adb- isA- 6 JB- 12 JC- 24 JD- 18 J

The correct option is C 24 JAS internal energy is state variable Δ U is same for both nbsp; process acb and adb First law of thermodynamics for process acb ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Heat Engines

When a system...

Question

When a system is taken from state $‘ a^{'}$ to state $‘ b^{'}$ along the path $‘ a c b^{'}$ , it is found that a quantity of heat $Q = 200 J$ is absorbed by the system and a work $W = 80 J$ is done by it. Along the path $‘ a d b^{'}, Q = 144 J$ . The work done along the path $‘ a d b^{'}$ is

6 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

12 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

18 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

24 J

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $24 J$
AS internal energy is state variable $Δ U$ is same for both process $a c b$ and $a d b$
First law of thermodynamics for process $a c b$ gives
$Δ U_{a b} = Δ Q_{a c b} - Δ W_{a c b} = 200 - 80 = 120 J$
First law of thermodynamics for process $a d b$ gives
$Δ W_{a d b} = Δ Q_{a d b} - Δ U_{a b}$
$= 144 - 120 = 24 J$

Suggest Corrections

Similar questions

Q. When a system is taken from the state 'a' to state 'b' along the path 'acb', it is found that a quantity of heat

Q = 200 J

is absorbed by the system and a work

W = 80 J

is done by it. Along the path 'adb',

Q = 144 J

. The work done along the path 'adb' is

Q. When a system is taken from state 'a' to state 'b' along the path 'acb' it is found that a quantity of heat Q = 200 J is absorbed by the system and a work w = 80J is done by it. Along the path 'abd' Q = 144 J The work done along the path 'adb' is:

Q. When a system is taken from state A to state B along the path ACB, 80J of heat flows into the system and the system does 30J of work.
(A) How much heat flows into the system along path ADB if the work done is 10J?
(B) When the system is returned from state B to A along the curved path, the work done on the system is 20J. Does the system absorb or liberate heat and how much?
(C) If

U_{D} - U_{A} = 40 J

, find the heat absorbed in the process AD and DB.

Q. A system is taken from state A to state B along 2 different paths 1 and 2 . The heat absorbed and work done by the system along these 2 paths are

Q_{1}

Q_{2}

and

W_{1}

W_{2}

Q. When a system is taken from state

1 t o 2

along the path

1 a 2

it absorbs

50 c a l

of heat and work done is

20 c a l

. Along the path

1 b 2

Q = 36 c a l

. What is the work done along

1 b 2

Join BYJU'S Learning Program

When a system is taken from state ‘a′ to state ‘b′ along the path ‘acb′, it is found that a quantity of heat Q=200 J is absorbed by the system and a work W=80 J is done by it. Along the path ‘adb′,Q=144 J. The work done along the path ‘adb′ is

The correct option is D 24 JAS internal energy is state variable ΔU is same for both process acb and adb First law of thermodynamics for process acb gives ΔUab=ΔQacb−ΔWacb=200−80=120 J First law of thermodynamics for process adb gives ΔWadb=ΔQadb−ΔUab =144−120=24 J