When acetamide is treated with $N a O B r$ , the product formed is:

C H_{3} C N

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C H_{3} C H_{2} N H_{2}

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C H_{3} N H_{2}

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none of the above

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Solution

The correct option is C $C H_{3} N H_{2}$
Acetamide, when treated with $N a O B r$ gets converted to methylamine as shown in the figure. This reaction is also known as Hoffman Bromamide synthesis

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[CPMT 1993]

C H_{3} C N + 4 H N a / C_{2} H_{5} O H \to C H_{3} C H_{2} N H_{2}

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