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Variable Oxidation States

When acidifie...

Question

When acidified $K_{2} C r_{2} O_{7}$ solution is added to $S n^{2 +}$ salts, then $S n^{2 +}$ changes to:

S n

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S n^{3 +}

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S n^{4 +}

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S n^{+}

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Solution

The correct option is B $S n^{4 +}$
$K_{2} C r_{2} O_{7}$ being an oxidizing agent converts $S n^{2 +}$ into its highest oxidation state as $S n^{4 +}$

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Similar questions

K_{2} {C r}_{2} O_{7}

{S n}^{+ 2}

{S n}^{+ 2}

2 F e^{3 +} (a q) + S n^{2 +} (a q) \to 2 F e^{2 +} (a q) + A

[1] P b^{2 +} > P b^{4}, S n^{2 +} > S n^{4 +}

[2] P b^{2 +} < P b^{4}, S n^{2 +} < S n^{4 +}

[3] P b^{2 +} > P b^{4}, S n^{2 +} < S n^{4 +}

[4] P b^{2 +} < P b^{4}, S n^{2 +} > S n^{4 +}

[5] S n^{2 +} < P b^{2 +}, S n^{4 +} > P b^{4 +}

[6] S n^{2 +} < P b^{2 +}, S n^{4 +} < P b^{4 +}

Stability of ions of $G e, S n, a n d P b$ will be in the order:

F e C l_{3}

F e C l_{2}

S n C l_{2}

S n

S n^{4 +}

S n^{2 +}

F e C l_{3}

S n

H C l

F e C l_{3}

F e C l_{2}

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