When aluminum oxide $(A l_{2} O_{3})$ is electrolyzed for the production of aluminum metal. For a given quantity of electricity, the number of moles of aluminum obtained if the volume of $O_{2}$ gas obtained is $201.6$ liter measured at $N T P$ is_____________.

9

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6

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12

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4.5

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Solution

The correct option is D $12$
Number of equivalents of oxygen $= \frac{201.6}{5.6} = 36$
(Equivalent volume of oxygen $= 5.6 l i t r e$ at NTP)
$∴$ Number of equivalents of $A l = 36$
Mass of aluminium $= 36 \times 9 g$
Number of moles of aluminium $= \frac{36 \times 9}{27} = 12$ .

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