When an aqueous solution of sodium fluoride is electrolysed, the gas liberated at anode is $O_{2}$ .
If true enter 1, else enter 0.

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Solution

When an aqueous solution of sodium fluoride is electrolysed, the gas liberated at anode is $O_{2}$ and the gas liberated at cathode is $H_{2}$ .
At cathode, $2 H^{+} + 2 e^{-} \to H_{2} ↑$
At anode, $4 O H^{-} \to 2 H_{2} O + O_{2} + 4 e^{-}$
The discharge potential of hydrogen ions is lower than the discharge potential of sodium ions.
The discharge potential of hydroxide ions is lower than the discharge potential of fluoride ions.

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