Question

When an oxide ${M_{2}O}_3$ is oxidised to ${M_{2}O}_5$, then its equivalent weight becomes:

• A. Molecular Weight/1
• B. Molecular Weight/2
• C. Molecular Weight/4
• D. Molecular Weight/8

Answer 1

The correct option is B Molecular Weight/2

Equivalent weight $=\frac{Molecularweight}{valencyfactor}$

Valency factor is 2 because oxidation state of M in $M_2{O}_3$ is +3 and oxidation state of M in $M_2{O}_5$ is +5.

$\therefore 5-3=2$.

Hence, Equivalent weight $=\frac{M.w.}{2}$