When boron is fused with NaOH, products formed are

Na₂B₄O₇ and H₂

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NaBO₂ and H₂

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Na₃BO₃ and H₂

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B₂O₃ and H₂

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Solution

The correct option is C
Na₃BO₃ and H₂

$B + 6 N a O H \to 2 N a_{3} B O_{3} + 3 H_{2}$

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