CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

When burnt in air, 14.0 g mixture of carbon and sulphur gives a mixture of CO2 and SO2 in the volume ratio of 2:1 by volume. Being measured at the same conditions of temperature and pressure, number of moles of carbon is:

A
0.75
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.5
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
0.40
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.25
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 0.5
The volume ratio produced = 2:1
That means double the moles of carbon dioxide is produced
Let, mass of carbon = x g
Mass of S = (14x) g

Moles of carbon= x12

Moles of S = 14432

and we have

2×moles of carbon=moles of S

2×x12=14x32

On soving, we get x = 6 g

Moles of carbon = 612=0.5

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Stoichiometric Calculations
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon