Question

When burnt in air, 14.0 g mixture of carbon and sulphur gives a mixture of CO2 and SO2 in the volume ratio of 2:1 by volume. Being measured at the same conditions of temperature and pressure, number of moles of carbon is:

A
0.75
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B
0.5
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C
0.40
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D
0.25
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Solution

The correct option is A 0.5The volume ratio produced = 2:1That means double the moles of carbon dioxide is producedLet, mass of carbon = x gMass of S = (14−x) gMoles of carbon= x12Moles of S = 14−432and we have2×moles of carbon=moles of S2×x12=14−x32On soving, we get x = 6 g∴ Moles of carbon = 612=0.5

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